***********PLEASE INDICATE FINAL ANSWERS CLEARLY************* Item 2 A ladder of

Question

***********PLEASE INDICATE FINAL ANSWERS CLEARLY*************

Item 2 A ladder of length 20.0 m is carried by a fire truck. The ladder has a weight of 3200 N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Figure 1) you can ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is a distance 8.0 m from A, and the force F exerted by the piston makes an angle of 0 340 with the ladder. Figure 1 of 1 12.0 m 8.0 m Part A What magnitude must F have to just lift the ladder off the support bracket at B? Express your answer using two significant figures. Submit My Answers Give Up

Explanation / Answer

let's apply torques relative to B, so you will find the force : F

F*sin(40)*8 - 3200*10 = 0

==> 3200*10=Fsin40*8
==>F=6222.89 N

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