CORRECT ANSWER IS 32.45 PLEASE SHOW ME HOW TO GET THIS ANSWER A circular coil wo

Question

CORRECT ANSWER IS 32.45

PLEASE SHOW ME HOW TO GET THIS ANSWER

A circular coil wound 39 times with a radius of 0.44 meters is spun inside a magnetic field of 0.2 T to form a generator. This generator is connected to the primary side of a transformer where the number or turns on the primary side is 48 and the number of turns on the secondary side is 20. At what frequency does the coil need to be spun at such that the maximum current on the secondary side is 31 A if the resistance of the secondary side is 13 Ohms? Answer in Hz.

A circular coil wound 39 times with a radius of 0.44 meters is spun inside a magnetic field of 0.2 T to form a generator. This generator is connected to the primary side of a transformer where the number or turns on the primary side is 48 and the number of turns on the secondary side is 20. At what frequency does the coil need to be spun at such that the maximum current on the secondary side is 31 A if the resistance of the secondary side is 13 Ohms? Answer in Hz.

32.45 ± 10%

Explanation / Answer

B= Vmax /N *A*omega   

Vsecondary of transformer= IR = 13*31 = 403V

Vprimary = Np / Nsec * Vsecondary = 48/20 *403 =967.20V(this is the maximum voltage in generator)

Therefore omega=Vmax /N *A*B = 967.2/(39*pi*o.44^2 *0.2) =203.88rad/s

frequency in farads = omega/2pi = 203.88/2*pi =32.449Hz

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