A certain superconducting magnet in the form of a solenoid of length 0.56 m can

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Explanation / Answer

The number of turns in the solenoid can be calculated using following formula:

B = µ0*N*I / h

Where µ0 = magnetic constant = 1.2566*10^-6 H/m

N = number of turns required over here

I = current in amperes = 95 A

h = length of solenoid in meters = 0.56 m

B = magnetic field in teslas = 4 T

Putting all these values in the main equation mentioned at the top,

4 = (1.2566*10^-6)*N*(95) / (0.56)

=> No of turns in the solenoid = N  = 18764 turns

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