Determine a general expression for the moment of inertia of a meter stick I_e of

Question

Determine a general expression for the moment of inertia of a meter stick I_e of mass m in kilograms pivoted about point P. any distance d in meters from the zero-cm mark. I_e = Select from the variables below to write your expression. Note that all variables may not be required. alpha, beta, theta, a, b, c, d, g, h, j, k, m, P, S, t The meter stick is now replaced with a uniform yard stick with the same mass of m = 749 g. Calculate the moment of inertia in kg.m^2 of the yard stick if the pivot point P is at the 50-cm mark. Numeric: A numeric value is expected and not an expression. I_f =

Explanation / Answer

here,

Part A:
From Parallel axis theroam, moment of inertia is given as,

I = Io + md^2

I = Ml^2/12 + md^2

Part B:
LEngth of meter stick, l = 1 m ( always)
distance of pivot point, d = 50 cm = 0.5 m
mass of stick, m = 749 g = 0.749 kg

I = 0.749*1^2/12 + 0.749*0.5^2

I = 0.25 Kg.m^2

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