Q: An object of mass M = 5.30 kg is suspended from a spring of spring constant k
ID: 1492791 • Letter: Q
Question
Q: An object of mass M = 5.30 kg is suspended from a spring of spring constant k = 187 N/m.
A) Give the formula for the displacement of the end of the spring due to the weight of the mass. (Do not substitute numerical values; use variables only. Use the following as necessary: the object's mass M, spring constant k, and magnitude of gravitational acceleration g.)
|x| = ________
B) Calculate the displacement (in m) of the end of the spring due to the weight of the mass. (Enter your answer to at least three significant figures.)
|x| = ________ m
Explanation / Answer
(a)
Weight of the mass, = M*g
Spring Force is given by , F = k*x
On Hnaging mass in equilibrium, the two forces would be equal to each other,
So,
k*x = M*g
x = M*g/k
(b)
Substituing Values in above Formula,
x = (5.3*9.8)/(187)
x = 0.2778 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.