WHAT S THE PART G ? Cathode-ray tubes (CRTs) are often found in oscilloscopes an

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WHAT S THE PART G ?

Cathode-ray tubes (CRTs) are often found in oscilloscopes and computer monitors. In the figure (Figure 1) an electron with an initial speed of 6.50×106 m/s is projected along the axis midway between the deflection plates of a cathode-ray tube. The potential difference between the two plates is 21.0 V and the lower plate is the one at higher potential.

Part A

What is the magnitude of the force on the electron when it is between the plates?

1.68×1016

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Part B

What is the direction of the force on the electron when it is between the plates?

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Part C

What is the magnitude of the acceleration of the electron when acted on by the force in part (a)?

1.84×1014

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Part D

What is the direction of the acceleration of the electron when acted on by the force in part (a)?

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Part E

How far below the axis has the electron moved when it reaches the end of the plates?

7.86×103

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Part F

At what angle with the axis is it moving as it leaves the plates?

14.7

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Part G

How far below the axis will it strike the fluorescent screen S?

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Please answer PART G ???

Figure 1 of 1

Physics II

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Homework set 6

Problem 23.63

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Cathode-ray tubes (CRTs) are often found in oscilloscopes and computer monitors. In the figure (Figure 1) an electron with an initial speed of 6.50×106 m/s is projected along the axis midway between the deflection plates of a cathode-ray tube. The potential difference between the two plates is 21.0 V and the lower plate is the one at higher potential.

Part A

What is the magnitude of the force on the electron when it is between the plates?

F =

1.68×1016

  N  

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Correct

Part B

What is the direction of the force on the electron when it is between the plates?

Upward Downward

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Correct

Part C

What is the magnitude of the acceleration of the electron when acted on by the force in part (a)?

a =

1.84×1014

  m/s2  

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Correct

Part D

What is the direction of the acceleration of the electron when acted on by the force in part (a)?

Upward Downward

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Correct

Part E

How far below the axis has the electron moved when it reaches the end of the plates?

7.86×103

  m  

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Correct

Part F

At what angle with the axis is it moving as it leaves the plates?

=

14.7

    

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Correct

Part G

How far below the axis will it strike the fluorescent screen S?

D =   m  

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Please answer PART G ???

Figure 1 of 1

Explanation / Answer

Part A to Part F already solved in your question. However if you feel any problem, please comment

Part G

The total drop is a combination of the drop from the plates (calculated in (part E)) and the drop afterward (from simple trig) :-

Delta Y = delta Yc +12.0 x 10-2* tan(14.7) = 7.86×103 + 0.12*0.2623 =0.0393 m...........Ans.

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