I have a 9 V battery and 3 10 ohm resistors. If I hook up the three resistors in
ID: 1493575 • Letter: I
Question
I have a 9 V battery and 3 10 ohm resistors. If I hook up the three resistors in series, what is the total current through the circuit? What is the voltage drop across each resistor?) I have a 9 V battery and 3 10 ohm resistors. If all three resistors are hooked up to the battery in parallel, what is the current coming out of the battery? What is the current through each of the resistors? What is the voltage drop across each? How much power is radiated by the resistors in Problem 1? How much power is being radiated by the resistors in Problem 2? Which battery do you think would die faster? Problems 4-6 deal with the following figure: What is the equivalent resistance of the circuit? What is the total amount of current that flows out of the battery? Calculate the current through each of the resistors in the circuit. Calculate the voltage drop across each of the resistors in the circuit. A 12 V car battery, when connected in a circuit, is able to deliver a potential difference of 8.4 V while providing 75 A of electricity. What is the internal resistance of the car battery? Suppose you have three resistors with resistance: 100 ohm, 50 ohm, and 25 ohm. What are all of the possible configurations of the resistors? What are all of the equivalent resistances? More problems on the next page! Problems 9-10 deal with the following figure: What is the equivalent resistance of the circuit pictured if R = 120 ohm ? What is the total current through the circuit? How much power is radiated by the sum of the resistors?Explanation / Answer
1. R eq = 3*10 = 30 ohms [for resistors in series]
V = IR
9 = I*30
I = 0.3 A
dV across each resistor = I*r = 0.3*10 = 3 V
2. Req = 10/3 = 3.33 ohms [ for resistors in parallel]
V = IR
9 = I*10/3
I = 2.7 A
Current through each resistor = V/r = 9/10 = 0.9 A
V across each resistor = 9 v (parallel connection)
3. Power in case 1 = VI = 9*0.3 = 2.7 W
Power in case 2, VI = 9*2.7 = 24.3 W
Battery would die faster in case 2
4. 8 amd 4 ohm are in parallel, Req = (1/8 + 1/4)^-1 = 2.667 ohm
Req and 6 ohm are in series, so Req' = 8.667 ohms
Req' , 10 ohm are in parallel, Req" = (1/8.667 + 1/10)^-1 = 4.6428 ohm
r, 5 ohm and Req" are in series, so R = 10.142 ohm
V = IR
I = 9/R = 0.8873 A
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