Water flows steadily from an open tank as shown in the figure. The elevation of
ID: 1493706 • Letter: W
Question
Water flows steadily from an open tank as shown in the figure. The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×102 m2 ; at point 3, where the water is discharged, it is 1.60×102 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.Assuming that Bernoulli's equation applies, compute the volume of water V that flows across the exit of the pipe in 1.00 s . In other words, find the discharge rate V/t. Express your answer numerically in cubic meters per second.
Explanation / Answer
use bernoulli's equation for 1 to 3, take v1 to equal zero and P3 = P1
P1/pg + z1 = P3/pg + v3^2/2g + z3
v3 = sqrt(2g(z1 - z3))
Q = A3*v3 =1.60×102 * sqrt(2*9.81*(10 - 2))
Q=0.2004 m^3/s
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