A series RLC circuit consists of a 41.0 resistor, a 4.80 mH inductor, and a 330

Question

A series RLC circuit consists of a 41.0 resistor, a 4.80 mH inductor, and a 330 nF capacitor. It is connected to an AC source with a peak voltage of 4.40 V and a frequency of 3 kHz.

Part A

What is the angular frequency of the AC source?

Part B

Determine the reactance of the inductor.

Part C

Determine the reactance of the capacitor.

Part D

Determine the impedance of the circuit.

Part E

Determine the peak current.

Part F

Determine phase angle.

Part G

Find the current in the circuit at t=35 s

Part H

Find the voltage across the resistor at t=35 s

Part I

Find the voltage across the inductor at t=35 s

Part J

Find the voltage across the capacitor at t=35 s

Explanation / Answer

PART A

angular frequency= 3000Hz

PART B

Reactance of inductance = wl

=2*3.14*3000*4.8*0.001

=90.47 ohms

PART C

Reactance of capacitor= 1/wc

=1/2*3.14*330*3000*10^-9

=160.8 ohms

PART D

Impedence =(r2*wl2*1/wc2)^1/2

=(41^2*160.8^2*90^2)^1/2

=188 ohms

PART E

Peak current= v/z

=4.4/188

=0.0234 Amperes

PART F

Phase angle = tan inv (90.47/160.8)

=29.36 degrees

PART G

Current= 35*10^-6/60*0.0234

=13.65 nA

PART H

Voltage= 35*10^-6*41*0.0234

=55.97 nV

PART I

Voltage= 35*10^-6/60*0.0234*90.47

=1.235*10^-6 V

PART J

Voltage= 35*10^-6/60*0.0234*160.8

=2.19*10^-6 V

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