Three forces are applied to a wheel of radius 0.350 m, as shown in the figure (F

Question

Three forces are applied to a wheel of radius 0.350 m, as shown in the figure (Figure 1) . One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0 angle with the radius. Assume that F1=11.8N, F2=15.2N, and F3=8.80N.

Part A

What is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? Indicate the direction of the net torque by letting counterclockwise torques be positive.

Express your answer in newton meters to three significant figures.

= _____________ Nm

Explanation / Answer

Torque, t = (perpendicular component of force to the moment arm)*(length of arm)
Perpendicular component of F1 = F1sin(0) = 0
Perpendicular component of F2 = F2sin(40) = 15.2sin(40) = 9.77 N
Perpendicular component of F3 = F3sin(90) = 8.8 N

Net t = 8.8*0.35 - 9.77*0.35 = -0.3395 Nm [cvlockwise]

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