You would like to observe an E. coli bacterium that is 1.85 mu m long. Because d

Question

You would like to observe an E. coli bacterium that is 1.85 mu m long. Because diffraction blurs an image, you would like to minimize the effects of diffraction by using a wavelength no larger than the object you are observing. For this problem, assume the wavelength is equal to the length of the bacterium. What is the energy of a photon with this wavelength? What is the energy of an electron with a de Broglie wavelength of this size? In terms of energy, which particles, photons or electrons, are the least likely to damage your sensitive biological sample?

Explanation / Answer

p = h/lambda

p = sqrt(2E*m)

sqrt(2E*m) = h/lambda

square both side

2E*m = h^2/lambda^2

m = mass of electron

E = h^2/lambda^2*2m

E = 7.06 x 10^-26 J

part c )

electron , thety have less energy compare to photons

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