A circuit is constructed with five capacitors and a battery as shown. The values

Question

A circuit is constructed with five capacitors and a battery as shown. The values for the capacitors are: C1 = C5 = 2.9 F, C2 = 3.6 F, C3 = 5.2 F, and C4 = 3.2 F. The battery voltage is V = 12 V.

3)

What is Q5, the charge on capacitor C5?C

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4)

What is Q2, the charge on C2?C

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5)

What is Q1, the charge on capacitor C1?C

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6)

What is V4, the voltage across capacitor C4?

Explanation / Answer

The capacitance across ab is

Cab= [C2C3/C2+C3]+C4 =5.327 uF

The capacitance across ac is

Cac = [1/Cab + 1/C1]^-1 = 1.8777 uF

Total capacitance is

C= [1/Cac + 1/C5] ^-1 =1.14 uF

Total charge is

Q=CV=13.68 uC

Capacitors C1 and C5 are in series combination

So both have the same charge

Q1=Q5=13.68 uC

Voltage V4 is

V4 =13.68 / 5.327 = 2.568 V

Charge Q2

Q2= C2V = 3.6*2.568= 9.2448 V

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