Two compact sources of sound oscillate in phase with a frequency of 100 Hz where

Question

Two compact sources of sound oscillate in phase with a frequency of 100 Hz where the speed of sound is 340 m/s. At a point that is 5.60 meters from one source and 5.94 meters from the other, the amplitude of the sound from each source separately is A.

Two compact sources of sound oscillate in phase with a frequency of 100 Hz where the speed of sound is 340 m/s. At a point that is 5.60 meters from one source and 5.94 meters from the other, the amplitude of the sound from each source separately is A (a) What is the phase difference in the sound waves from the two sources at that point? rad (b) What is the amplitude of the resultant wave at that point? ×A

Explanation / Answer

given

f = 100 hz

v = 340 m/s

r1 = 5.6 m

r2 = 5.94 m

let lamda is the wavelength of the sound.

a) apply, v = lamda*f

==> lamda = v/f

= 340/100

= 3.4 m

phase diifrence = (2*pi/lamda)*path difference

= (2*pi/lamda)*(r2-r1)

= (2*pi/3.4)*(5.94 - 5.6)

= 0.628 rad

b) resultant amplitude = 2*A*cos(phi)

= 2*A*cos(0.628)

= 1.62*A

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.