You will need to draw your own velocity selector to answer this question. In you

Question

You will need to draw your own velocity selector to answer this question. In your V.S., you determine that you need alpha particles (mass 6.68x10-27kg, charge +3.20x10-19C) to move at a constant velocity of 3.93x105 m/s in the + direction. You set up a capacitor to produce an electric field with the top plate 1.00cm above the x-y plane, and the bottom plate 1.00cm below the x-y plane. You produce a magnetic field of B = 1.51T in the + direction. Given this information, what does the voltage of the top plate need to be with respect to the bottom plate?

Explanation / Answer

magnetic force is equal to electric force

qvB = q E

E = vB

relation of potential difference and distance is

E = del V d

del V d = vB

del V = vB/ d = 3.93x105 m/s(1.51)/0.02 m = 2.96 * 10^7 V

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