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Select from the following for the next question: A real, upright and larger than

ID: 1497498 • Letter: S

Question

Select from the following for the next question: A real, upright and larger than the object B real, Inverted and smaller than the object C virtual, Inverted and larger than the object D virtual, upright and larger than the object E virtual, inverted and smaller than the object F real, Inverted and larger than the object G real, upright and smaller than the object H virtual, upright and smaller than the object An object is placed 14.5 cm away from a converging lens. The lens has a focal length describes the Image.

Explanation / Answer

The expression that controls the imaging lenses is

1/f = 1/o + 1/i

where

f is the focal length

o is the distance from the lens to the object

i is the distance from the lens to the image

the image is real if the light rays pass through it

the image is virtual if the extensions of the rays pass through it

let's look at this case

Data

o = 14.5 cm

f = 10.0 cm

o > f

1/i = 1/f - 1/o   

1/i = 1/10 – 1/14.5

1/i = (14.5 – 10)/ ( 14.5 10)

1/i = 4.5 /145

i = 32.2 cm

i is positive

m= - i/o

m = - 32.2/ 14.5

m = - 2.2

i is positive so the image is real,

like this on the other side of the lens is INVERTED

the magnicacion is greater than 1 so the image is larger than the object

when we compare with the expressions the correct is F

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