Consider a modified version of the flux experiment that we did in lab using the

Question

Consider a modified version of the flux experiment that we did in lab using the nails. If the density of nails in the board was 1 nail every cm^2. What would be the flux of nails that would pass through a circular loop of wire that had a radius of 10 cm and was tilted at an angle of Theta = 20Degree from the vertical. Assume that the nails are pointing straight upward A solid conducting sphere has a charge of Q on it. What is the strength of the electric field outside the sphere. Use Gauss's law to show how you derived at the answer. Simply stating the answer will not get you any points. You must show the derivation.

Explanation / Answer

HW3:

flux of nails through the given loop = 10*cos(20)

= 9.397

HW4)

let R is the radius of the sphere.

Imagine a sphecrical surface with radius r

so, Qin = Q

now use gauss's law

integral E.ds = Qin/epsion

E*4*pi*r^2 = Q/(epsilon)

E = Q/(4*pi*epsilon*r^2)

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