In a photoelectric experiment, 249-nm ultraviolet light shines on an aluminum ta

Question

In a photoelectric experiment, 249-nm ultraviolet light shines on an aluminum target.

What's the energy of the electrons that emerge?

Here is what I tried:

wavelength = 249 * 10^-9 m

work function of aluminum = 4.08eV

Kmax = hf - workfunction

since f = c / lambda

Kmax = hc/lambda - workfunction

Kmax = ((6.63*10^-34 J*s) * (3.0 *10^8 m/s)) / (249*10^-9m) - 4.08eV

Kmax = 7.98795181*10^-19 J - 4.08eV

Kmax = ~4.99eV - 4.08eV = .912eV

Mastering physics says the answer is .706eV

Can you tell me what I did wrong?

Explanation / Answer

you done everything correct and your answer is correct

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