Steam at 120 C and at atmospheric pressure of 101.3 kPa is added to a hollow cyl

Question

Steam at 120 C  and at atmospheric pressure of 101.3 kPa  is added to a hollow cylindrical steel can that is then sealed and allowed to cool. The can is 0.20 m tall and 0.10 m in diameter, and the can stands on the flat part of its surface.

Part A

What is the pressure inside the can at 101 C?

Part B

What is the magnitude of the total force exerted by the atmosphere on the whole curved portion of the can exterior?

Part C

What is the magnitude of the force exerted by the atmosphere on the top flat portion of the can exterior?

Explanation / Answer

Here

T1 = 120 degree C = 393 K

T2 = 101 degree C = 374 K

a)

P1 = 101.3 kPa

Using ideal gas equation

P1/T1 = P2/T2

101.3/393 = P2/374

P2 = 96.40 kPa

the pressure inside the can is 96.40 kPa

b)

magnitude of total force extered by exerted on the curved portion = projected area * pressure

magnitude of total force extered by exerted on the curved portion = 0.20 * 0.10 * 1.01 *10^5 Pa

magnitude of total force extered by exerted on the curved portion = 2020 N
c)

magnitude of force exerted by atmosphere on the top flat portion = pi * (r)^2 * pressure

magnitude of force exerted by atmosphere on the top flat portion = pi * (0.10/2)^2 * 1.01 *10^5 N

magnitude of force exerted by atmosphere on the top flat portion = 793.1 N

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