I need answers and work shown for Part 2 only. I need all times calculated based

Question

I need answers and work shown for Part 2 only. I need all times calculated based on the percentages, not just one... please.

Chegg BoOKS STUDY MORE> BOOKS STUDY MORE Find books, solutions, tutors and mo Question 1. An RC Circuit is constructed with a 1200 resistor and a 2 F capacitor connected to 10V. a) What is the initial current in the circuit? b) How, long does it take for the capacitor to build up 80% of the total charge it can hold? 90%? 99%? 2. Consider another RC circuit, where a resistor of 600 is connected to the 2F capacitor and a 10V battery a) How long does it take for the capacitor to build up 80% of the total charge it can hold? 90%? 99%? b) How do these values compare to the values you found in question 1? Looking for the answer to question number 2 but you made need information from question 1. Comment Expert Answer Anonymous answered this 9 minutes later Was this answer helpful? | | | 0 2,985 answers 1) a) Initial current is 10/1200 8.33 mA b) Time constant " RC = 1200*2*10^-6-2.4 ms

Explanation / Answer

1)

resistance, R=1200 ohms

capacitance, C=2*10^-6 F

battery potential. v=10v

a)

initial current, i=io=V/R

=10/1200

=8.33*10^-3 A

=8.33 mA

b)

time constant, T=R*C

T=1200*2*10^-6

T=2.4*10^-3 sec

T=2.4 msec

now,

q=qo*(1-e^-t/T)

now,

i)

if q=80% of qo

q=(80/100)*qo

q=0.8*qo

now,

q=qo*(1-e^-t/T)

0.8*qo=qo*(1-e^-t/T)

0.8=(1-e^-(t/(2.4*10^-3)))

====> t=3.86*10^-3 sec

t=3.86 msec ------------------->

ii)

if q=90% of qo

q=(90/100)*qo

q=0.9*qo

now,

q=qo*(1-e^-t/T)

0.9*qo=qo*(1-e^-t/T)

0.9=(1-e^-(t/(2.4*10^-3)))

====> t=5.53*10^-3 sec

t=5.53 msec --------------->

iii)

if q=99% of qo

q=(99/100)*qo

q=0.99*qo

now,

q=qo*(1-e^-t/T)

0.99*qo=qo*(1-e^-t/T)

0.99=(1-e^-(t/(2.4*10^-3)))

====> t=11.05*10^-3 sec

t=11.05 msec ---------------->

2)

resistance, R=600 ohms

capacitance, C=2*10^-6 F

battery potential. v=10v

a)

time constant, T=R*C

T=600*2*10^-6

T=1.2*10^-3 sec

T=1.2 msec

now,

q=qo*(1-e^-t/T)

i)

if q=80% of qo

q=(80/100)*qo

q=0.8*qo

now,

q=qo*(1-e^-t/T)

0.8*qo=qo*(1-e^-t/T)

0.8=(1-e^-(t/(1.2*10^-3)))

====> t=1.93*10^-3 sec

t=1.93 msec ------------------->

ii)

if q=90% of qo

q=(90/100)*qo

q=0.9*qo

now,

q=qo*(1-e^-t/T)

0.9*qo=qo*(1-e^-t/T)

0.9=(1-e^-(t/(1.2*10^-3)))

====> t=2.76*10^-3 sec

t=2.76 msec --------------->

iii)

if q=99% of qo

q=(99/100)*qo

q=0.99*qo

now,

q=qo*(1-e^-t/T)

0.99*qo=qo*(1-e^-t/T)

0.99=(1-e^-(t/(1.2*10^-3)))

====> t=5.53*10^-3 sec

t=5.53 msec ---------------->

b)

here,

time calculated in part(2) is half of the time calculated in part (1)

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.