fig 7 (FA-8) shows a solid cylindrical rod of radius 6.50 cm carrying a current

Question

fig 7 (FA-8) shows a solid cylindrical rod of radius 6.50 cm carrying a current of 25.0 A into the page, concentric with a thick walled cylinder of inner radius b = 25.0, cm and outer radius = 28.0 cm, carrying a current of 15.0 A out of the page. What is the magnetic field (magnitude and direction) B(r = 21.0 cm), i.e., at 21.0 cm from the common axis. Give your answer in the form "a.bc x 10^(y)" T, "CW" for clockwise or "CCW" for counterclockwise. For example, if your answer is 15 mT, clockwise then input your answer as
d)Determine the magnetic field (magnitude and direction) B at 30.0 cm from the common center. Give your answer in the format that is indicated in problem #5a.
b)Determine the magnetic field (magnitude and direction) B at 1.5 cm from the common center. Use micro Tesla as the units for your answer and give your answer in the same format that you used in 5a.

Explanation / Answer

magnetic field due to current carrying wire = k * I / r

magnetic field at 30 cm from the common center

magnetic field due to inside wire = 2 * 10^-7 * 25 / 0.30

magnetic field due to outside wire = 2 * 10^-7 * 15 / 0.30

since the direction of the current is opposite the magnetic field due to both the wires will be in opposite direction

so net magnetic field = 2 * 10^-7 * 25 / 0.30 - 2 * 10^-7 * 15 / 0.30

net magnetic field at 30 cm from the common center = 6.67 * 10^-6 T

net magnetic field at 1.5 cm from the common center = 0 T

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.