then filled with an unknown gas to a final pressure equal to atmospheric pressur

Question

then filled with an unknown gas to a final pressure equal to atmospheric pressure at standard temperature. If in the process of filling exactly 23 fringes are counted on the interferometer, determine what the index of refraction for the unknown gas is at atmospheric pressure and standard temperature. A Keplerian telescope can be converted into a practical terrestrial telescope with the addition of two more lenses. Describe how one might do this using two identical lenses in addition the eyepiece and objective lenses. Also provide a quantitative description of how the additional lenses should be placed using figures, equation, and/or numbers. A vanity mirror is essentially a mirror than functions as a simple magnifier with the user's face as the object. Given that a particular vanity mirror is designed to work when a person is within a distance of 6.0 cm, what is the angular magnification of the mirror? Recall that there are two formulas for the magnification of a simple magnifier, one corresponding to a virtual image infinitely far away that minimizes eye strain, and one that achieves the optimum angular magnification. Compare the contrast this with the vanity mirror. Are these two cases also there for the vanity mirror? How should the formulas for angular magnification be modified, if at all? Note that unlike a simple

Explanation / Answer

The telescope case all you need is to put in eye lenses to change the image inverted a right image, the objective of this is that the floor is down. The most used configuration is the placement of two convergent lenses it gives a distance of 2f including

The mirror case is a bit more delicate

The expressions for the magnification are

m = h'/ h = - i/o

m = / o

where

h' It is the height of the image

h is the height of the object

i distance image

o distance to the object is the angle o is the angle lens with direct eye seen

data

o = 6 cm

i = inf

We calculate the focal length of the mirror

1/o + 1/i = 1/f

1/f = 1/6 + 1/inf

1/f = 1/6

f = 6 cm

With this expression we substitute value of magnification of a simple magnifying glass, where the image is formed at infinity (far point vision)

m = 25/ f

m = 25/6

m = 4.166

Let's use the other form

remember that all measures are in radians

caual so we can relate the angles and distances

= h/o

o = h'/i

m = / o = (h/o)/ (h'/i)

m = h i / h'o

when the image is formed at the point of near vision i =25 cm

m = 1 + 25/f

m = 1 + 25/6

m = 5.16

the two magnifications are

m1 = 4.16

m2 = 5.16

It should be clarified that even if the m.2 magnification for near-vision point is greater, in this position the eyes make a great effort approach which is a stirring position therefore is rarely used.

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