IP A beam of vertically polarized light encounters two polarizing filters, as sh

Question

IP A beam of vertically polarized light encounters two polarizing filters, as shown in the figure(Figure 1) .

Part A

Rank the three cases, A, B, and C, in order of decreasing transmitted intensity.

Rank cases from highest to lowest transmitted intensities. To rank items as equivalent, overlap them.

Part B

Calculate the transmitted intensity for each of the cases in the figure, assuming that the incident intensity is 27.0 W/m2 .

Enter your answers numerically separated by commas.

IA, IB, IC = ___ W/m^2

Explanation / Answer

According to mauls law

I = Io (Cos(theta))^2

A.) I = 0

B.) I =Io (Cos(22.5))^2 *(Cos(0))^2

I = 0.853Io

C.) I =Io (Cos(22.5))^2 *(Cos(45))^2

I = 0.426Io

so Rank will be

B>C>A

Part B.)

IA = 0

B.) IB =Io (Cos(22.5))^2 *(Cos(0))^2

IB = 0.853*27 = 23.01 W/m^2

C.) IC =Io (Cos(22.5))^2 *(Cos(45))^2

IC = 0.426*27 = 11.502 W/m^2

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