The same charge is then moved a distance of 2 cm to another equipotential line t

Question

The same charge is then moved a distance of 2 cm to another equipotential line that has a value of 3.21 V. How much work was required to move this charge?

I know the answer is 2.7 uJ for it, but I don't know how. Please solve it for me to understand it. Thanks.

U16Q2 A charge of 2 C is moved 3 cm along an equipotential surface that has a value of 4.56V. How much work was required to move this charge along the surface? A)0 J B) 0.27u D) 27 J U16Q3 The same charge is then moved a distance of 2 cm to another equipotential line that has a value of 3.21 V. How much work was required to move this charge? A) 0J B) 0.27 D) 27J

Explanation / Answer

U16Q2:

Q = 2 uC, d = 3 cm

Here the potential change is zero hence the change in potential energy is zero hence no work done is required because the change in kinetic energy is also zero.

U16Q3:

The potential difference = V_2-V_1 = 3.21-4.56 = -1.35 V

Hence the change in potential energy = - 2*10^-6*1.35 = -2.70 uJ

So the required work done will be negative of the change in potential energy which is 2.7 uJ because again the kinetic energy is not being changed.

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