Two 2.2-mm-diameter beads. C and D. are 12 mm apart, measured between their cent

Question

Two 2.2-mm-diameter beads. C and D. are 12 mm apart, measured between their centers. Bead C has mass 1.0 g and charge 2.2 nC. Bead D has mass 2.5 g and charge -1.0 nC. If the beads are released from rest, what is the speed vq of C at the instant the beads collide? Express your answer to two significant figures and include the appropriate units. Submit Part B What is the speed of D at the instant the beads collide? Express your answer to two significant figures and include the appropriate units. Submit

Explanation / Answer

here linear momentum is conserve

m1v1 = m2v2

v2 = m1v1/m2

by energy conservation

kq1q2/r = m1v1^2/2 + m2v2^2/2

put the value of v2

kq1q2/r = 1/2 * ( 1+ m1/m2)m1v1^2

v1 = sqrt([2m2*kq1q2]/(r*m1*(m1+m2))

m2 = mass of bead D

m1 = mass of bead 1

v1 = 0.04855 = 0.049 m/s

part b )

v2 = m1v1/m2

v2 = 0.0194 = 0.019 m/s

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