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Monochromatic light falling on two slits 0.01 X mm apart product\'s the fifth-or

ID: 1502565 • Letter: M

Question

Monochromatic light falling on two slits 0.01 X mm apart product's the fifth-order bright fringe at an 8.6 degree angle. What is the wavelength of the light used? The third-order bright fringe of 610-nm light is observed at an angle of 31 degree when the light falls on two narrow slits. How far arc the slits? In a double-slit experiment it is found that blue light of wavelength 480 nm gives a second-order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location? If 680-nm light falls on a slit 0.0425 mm wide, what is the angular width of the central diffraction peak? Monochromatic light falls on a slit that is 2.60 x 10^-3 mm wide. If the angle between the first dark fringes on cither side of the central maximum is 28.0degree (dark fringe to dark fringe), what is the wavelength of the light used? When blue light of wavelength 440 nm falls on a single slit, the first dark bands on either side of center arc separated by 51.0degree. Determine the width of the slit. If a soap bubble is 120 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated normally by white light? Assume that n = 1.32. A lens appears greenish yellow (X S70 nm is strongest) when white light reflects from it. What minimum thickness of coating (- 1.25) do you think is used on such a glass lens (n = 1.52). and why?

Explanation / Answer

1. the nth fringe can be found by

n*lambda/d = x/L

where
n = the fringe order (=5)
lambda = wavelength
d = separation of slits (=1.8e-2 mm)
x = distance to the fringe from the zero order
L = distance from the slits to the screen

since you know the angle of the position of the 5th order slit, you can determine x/L by tan(theta)= x/L

Solve

5 * lambda / (1.8e-2) = tan(8.6 deg)

lamda = 5.44 x 10^-4 mm........Ans.

2.  dsin = n
dsin31 = 3(610*10^-9)
d(0.515) = 1830*10^-9
d = 3553.39*10^-9
d = 3.55*10^-6
d = 3.55 micrometers.

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