A spherical cloud of total charge + Q has radius R. The charge density of this c
ID: 1502887 • Letter: A
Question
Explanation / Answer
part a )
from gauss law = E.dA = Q/eo
E = Q/eo*4pi*r^2
V = kQ/r
part b )
speed will increase acceleratio will decrease
part c )
KE = change in work
KE = integral F.dr from r ot R = -KQqintegraldr/r^2 from r to R
KE = KQq*(1/R - 1/r )
part d )
Q = integral rho*dV from 0 to R
Q = integral rho_0(1-r/R) *4pi*r^2dr from 0 to R
Q =4pi*rho_0 integral (1-r/R)r^2dr = 4pi*rho_0 [ r^3/3 - r^4/4R] from 0 to R
= 4pi*rho_0* R^3 [ 1/3 - 1/4] = 4pi*rho_0 *R^3/12 = pi*rho_0*R^3 /3
rho_0 = 3Q/pi*R^3
part e )
E.dA = Q/eo
E.4pi/r^2 = 1/eo * integral rho*dV = 1/eo * integral rho_0(1-r/R)*4pi*r^2*dr
= 4pi*rho_0/eo * (r^3/3 - r^4/4R) from 0 to r
4pi*rho*r^3/eo * [ 1/3 - r/4R]
E = kQr/R^3 *[ 4 -3r/R]
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