(a) Assume that the string is vertical (it is perpendicular to the bar). Use the

Question

(a) Assume that the string is vertical (it is perpendicular to the bar). Use the equilibrium equation for the torques to find m2. (Your answer should be in terms of m1, d1, and d2.)
m2 =  

(b) Now consider the actual setup with the string at an angle ? to the vertical. Again use the equilibrium equation for the torques to find m2. (Your answer should be in terms of m1, d1, d2, and ?.)
m2 =  

(c) How much additional mass does the student have to add to the bucket to correct this error? (Your answer should be in terms of m1, d1, d2, and ?.)
m =  

Explanation / Answer

a) at equillibrium tension T = m2g

for equillibrium of bar net torque is balanced

m1g*d1 = m2g*d2

=> m2 =m1*d1/d2

b) string at an angle theta

T = m2g

net torque balanced

m1g*d1 = Tcos(theta)*d2 = m2gcos(theta)*d2

=> m2 = m1*d1/(d2*cos(theta))

c) additional mass to be added to correct the error

= [m1*d1/(d2*cos(theta))] - m1*d1/d2

= (m1*d1/d2)(sec(theta) - 1)

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