1.) Charges of -q and +2q are fixed in place, with a distance of 2 m between the
ID: 1504069 • Letter: 1
Question
1.) Charges of -q and +2q are fixed in place, with a distance of 2 m between them. A dashed line is drawn through the negative charge, perpendicular to the line between the charges. On the dashed line, at a distance L from the negative charge, there is at least one spot where the total potential is zero. Find L.
2.) Two protons are moving directly toward one another. When they are very far apart, their initial speeds are 1.20 x 105 m/s. What is the distance of closest approach?
3.) A positive point charge (q = +7.73 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 2.86 m. A positive test charge (q0 = +4.51 x 10-11 C) moves from surface A to another equipotential surface B, which has a radius rB. The work done by the electric force as the test charge moves from surface A to surface B is WAB = -6.85 x 10-9 J. Find rB.
The drawing shows a square, each side of which has a length of L = 0.250 m. Two different positive charges q1 and q2 are fixed at the corners of the square. Find the electric potential energy of a third charge q3 =-5.00 x 10-9 C placed at corner A and then at corner B Chapter 19, Problem 16 GO qi = + 1.50 x 10-9 C 92=+4.00 x 10-9 C EPEA EPEs EPEB-Explanation / Answer
4) PE of two point charge system:
PE = kq1q2/d
at A:
PE = [ (9 x 10^9 x 4 x 10^-9 x -5 x 10^-9)/(0.250)] + [ (9 x 10^9 x 1.50 x 10^-9 x -5 x 10^-9)/sqrt(0.250^2 + 0.250^2)]
+ [ (9 x 10^9 x 4 x 10^-9 x 1.50 x 10^-9)/(0.250)]
PEa = - 6.95 x 10^-7 J ........Ans
at B
PE = [ (9 x 10^9 x 1.50 x 10^-9 x -5 x 10^-9)/(0.250)] + [ (9 x 10^9 x 4 x 10^-9 x -5 x 10^-9)/sqrt(0.250^2 + 0.250^2)]
+ [ (9 x 10^9 x 4 x 10^-9 x 1.50 x 10^-9)/(0.250)]
PEa = - 5.63 x 10^-7 J ........Ans
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