A particular jet engine produces a tone of 512 Hz. Suppose that one jet is at re

Question

A particular jet engine produces a tone of 512 Hz. Suppose that one jet is at rest on the tarmac while a second identical jet flies overhead at 82.9% of the speed of sound. The pilot of each jet listens to the sound produced by the engine of the other jet. Which pilot hears a greater Doppler shift? Explain. The stationary pilot hears the greater Doppler shift since pilot is not moving the sound wavers between loud and quiet. Calculate the frequency heard by the pilot in the moving jet. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Hz Calculate the frequency heard by the pilot in the stationary jet. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Hz

Explanation / Answer

b)

Frequency heard by moving pilot = (1+v/c) * f = (1+0.829c/c) * 512

Frequency Heard = 936.44 Hz

c)

Frequency heard by stationary pilot = 1/(1-v/c) * f = 512/ (1-0.829) = 2.994 kHz

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