At certain distance r from a point charge q. the electric potential V:890.0 V th

Question

At certain distance r from a point charge q. the electric potential V:890.0 V the magnitude of the electric field is E = 17.6 N/C Determine the value of the charge Q. The Coulomb constant is: A: = 9.0 x 10^9 N.m^2/C^2 (6) A positron is accelerated from rest between two points due to a fixed greed electrostatic potential difference, and acquire upsilon_1 = (40/100)c, where c is the speed of light in free space(e= 3.0 x 10^4 m/a). Denote m_1 as the mass of a positron, a the charge of a positron and upsilon_1 the final velocity of the positron. a- Derive the equation that gives the magnitude of the potential difference |Delta V| between the two points. Ignore relativistic corrections. b- A proton is also accelerated from rest between the same two points What final speed_upsilon_2) will be reached by this proton? The mass of a positron is m 1 = 9.11 x 10^-31 kg and the mass of a proton is m2 = 1.67 x 10^-27 kg (7) A capacitor has a capacitance of 5.0 muF. What potential difference is require store a charge of 60.0 muC? (8) An electric charge +Q is placed in free space. Draw few equipotential due to this charge.

Explanation / Answer

5) E = k q / r2

E = V2 / k q

q = V2 / kE

q = 8902 / (9.0 * 109 * 17.6)

q = 5.00 * 10-6 C

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7) Q = C * V

Voltage = Charge / Capacitance = 60 * 10-6 / 5 * 10-6

= 12 V

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