1) Assume that the height of a type of bean plants is determined by five unlinke

Question

1) Assume that the height of a type of bean plants is determined by five unlinked genes called A, B, C, D, and E, and each gene has two alleles: additive (uppercase letter) and non-additive (lowercase letter). (a) The shortest plants are 130 cm. The tallest plants are 220 cm. Estimate how many centimeters each allele contributes to the height difference of 90 cm. [2 points] (b) The genotypes are known for two bean plants. Plant 1 is genotype A4BbccDdEE. Plant 2 is genotype aaBBCcDdEE. What are their heights? [2 points]

Explanation / Answer

Answer of (a)-

Uppercase latter that is AABBCCDDEE the number of allele is 10 so the tallest plant is 220 cm because all uppercase allele contribute to the height of plant so 220/10= 22 cm each uppercase allele contribute to the hieght of plant that is additive allele and non additive allele (lowercase letter) contribute to the hieght 130 cm and there is also 10 lowercase allele so 130/10= 13 cm contributed by each allele to 130cm.

Point that there is no additive effect of lowercase allele so called non additive allele and will not contribute in 90 cm of height. Height defferences of 90 cm is contributed by uppercase allele so the answer will be 90 cm/10= 9 cm for each uppercase allele.

Answer of (b)- Each uppercase allele have 22 cm contribution to the height for plant and each lowercase allele have 13 cm to the height for plant so AA=44, Bb=35, cc=26, Dd=35, EE=44

Then AABbccDdEE= 184 cm, for aa=26, BB=44, Cc=35, Dd=35,EE=44 then aaBBCcDdEE=184 cm

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