The adjacent graph represents the net horizontal force acting on an object as if

Question

The adjacent graph represents the net horizontal force acting on an object as if moves in a straight line along v-axis. What is the net work done by this force in the shown interval? 0 20 J 10 J -20 J Insufficient information. The adjacent graph represents a vertical map with the paths of two balls rolling from rest down two frictionless slopes with the indicated profile. Knowing that hall A is twice as heavy as B, which ball will move faster at the bottom of its hill, and what will be its speed? Ball A will move faster. vA = 19.8 m/s. Ball A will move faster, vA = 390 m/s. Ball B will move faster, vB = 19.8 m/s. Ball B will move faster, but the information is insufficient to find the speed. Both will move with the same speed. vA = vB =19.8 m/s

Explanation / Answer

Force at 1 m is,F=0.25 N

Force at 2 m is,F=10 N

Force at 3 m is,F=5 N,

Force at 4 m is,F=-5 N,

Force at 5 m is,F=-5 N,

Total Work done,W=The area under the curve. It is a combination of traingle and square. We know that area of triangle is (1/2)bh

b=base

h=height

Area of square of bh

So the Work done=(1/2)*10+(1/2)*5+1*5+(1/2)*2.5+(-5)=10 J

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.