A beam of light is polarized in a vertical plane and has an intensity I 0 . The
ID: 1504812 • Letter: A
Question
A beam of light is polarized in a vertical plane and has an intensity I0. The beam passes through an ideal polarizer and then through an ideal analyzer whose axis is set horizontally. If the axis of the polarizer is set at 60° with the vertical, what is the ratio of the intensity of the final beam to I0? A beam of light is polarized in a vertical plane and has an intensity I0. The beam passes through an ideal polarizer and then through an ideal analyzer whose axis is set horizontally. If the axis of the polarizer is set at 60° with the vertical, what is the ratio of the intensity of the final beam to I0?Explanation / Answer
given data
unpolarized intensity =Io
polarizer angle =60deg
when light passes through ideal polarizer
I1 = Io/2
when I1 passes through analyzer I2 is
from Malus law=I =Io cos^2(theta)
I2 = I1 cos^2(theta)
I2 = Io/2*cos^2 (60)=0.125*Io
I2/Io = 0.125
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