In a high-energy physics experiment, a neutral particle enters a bubble chamber

Question

In a high-energy physics experiment, a neutral particle enters a bubble chamber in which a magnetic field points into the page. Its velocity is shown in the figure. The neutral particle then decays into two charged particles. Initially both particles still move in the same direction as the initial velocity of the neutral particle. The subsequent trajectories of the charged particles are shown.

What is the sign of charged particle 1 and of charged particle 2? Which charged particle has a larger momentum? Explain. (Assume |q| = e for both particles)

Explanation / Answer

magnetic force Fb = q*(vxB)

here vxB is = (j x -k) = -i

for positive charge Fb = -i (-x axis) towards inner of particle 1

for positive charge Fb = + i( + x axis) towards inner of particle 2

particle 1 = positive charge

particle 2 = negative

++++++++++++++++++++

IN magnetic field

Fc = Fb

mv^2/r = qvB

r = mv/qB = p/qB

p = momentum

r = radius of circular path

P is large for larger radius

particle 2 is having larger momentum

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