At Hoover Dam, the distance the water effectively falls before encountering the

Question

At Hoover Dam, the distance the water effectively falls before encountering the electric generators depends on the water levels in Lake Mead. Assume that the water intakes are effectively 180 m above the electric generators. How much water must pass through the generators to power 2.1 million 27-W Las Vegas lightbulbs for 6.0 minutes? (HINT: This is a conservation of energy problem. All the energy comes from the falling water. Consider the electric generators to be 100% efficient.) Give your answer in kilograms, and enter your answer in the format *.**E**.

Explanation / Answer

h = 180 m

Potetial Energy will get converted to Electric Energy
Let the mass of water needed be m Kg.

Potenial Energy = m*g*h
P.E = m*9.8*180 J

Electrical Energy = 2.1 * 10^6 * 27 * 6.0 * 60 J
Electrical Energy =  2.0412 * 10^10 J

Using Energy Conservation
m*9.8*180 =  2.0412 * 10^10
m = 1.16 * 10^7 Kg

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