3 Learning Goal: To practice Problem-Solving Strategy 28.2 Ampere\'s Law. A soli

Question

3

Learning Goal: To practice Problem-Solving Strategy 28.2 Ampere's Law. A solid cylindrical conductor is supported by insulating disks on the axis of a conducting tube with outer radius R_a = 6.15 cm and inner radius R_b = 3.75 cm. (Figure 1) The central conductor and the conducting tube carry equal currents of I = 3.45 A in opposite directions. The currents are distributed uniformly over the cross sections of each conductor. What is the value of the magnetic field at a distance r Rank from largest to smallest the values of the magnetic field at the following distances from the axis of the conducting cylinder: R_a = 6.15 cm, R_b = 3.75 cm, r = 4.65 cm, and r > R_a. Rank from largest to smallest. To rank items as equivalent, overlap them.

Explanation / Answer

Here ,

Using Amphere circuital law

B * 2 pi * r = u0 * Iin

Iin the current inside the loop is Iin

r is the radius of loop

as the current in outer loop is in the oposite direction

the largest magnetic field is for Rb

then B at r

then B at Ra

B at r > Ra

the rank of the magentic field is

B at Rb

B at r

B at Ra

B at r > Ra

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