In a physics lab students are conducting an experiment to learn about the heat c

Question

In a physics lab students are conducting an experiment to learn about the heat capacity of different materials. The first group is instructed to add 1.5-g copper pellets at a temperature of 92°C to 125 g of water at 16°C. A second group is given the same number of 1.5-g pellets as the first group, but these are now aluminum pellets. Assume that no heat is lost to or gained from the surroundings for either group.

(a) If the final equilibrium temperature of the copper pellets and water is 25°C, how many whole pellets did the first group use in the experiment? The specific heat of copper is 0.0924 kcal/(kg · °C).

(b) What is the equilibrium temperature of the aluminum and water mixture for the second group?

Explanation / Answer

heat lost = heat gained

n*m1*S_cu*dT = m2*S_W*dT

n*1.5*0.0924*1000**10^-3*(92-25) = 125*1*(25-16)

no.of pellets are n = 121

b) heat lost = heat gained

n*m1*S_al*dT = m2*S_w*dT

121*1.5*10^-3*900*(92-T) = 125*10^-3*4186*(T-16)

equilibrium temperature is T = 34.1 degrees celsius

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