A 10kg block slides towards the 3kg moving block to create a totally inelastic h

Question

A 10kg block slides towards the 3kg moving block to create a totally inelastic head on collision. The 3kg block comes to a stop after the collision.

1. What speed must the 10kg block be moving at prior to the collision for this to occur?

2. Instead of sliding along a frictionless surface, suppose the 3kg block is now dropped from rest. After free falling through a height of 1m, it comes into contact with a vertically aligned massless spring. The block compresses the spring by 10m from its euqiollibrium position before finally coming to a stop. What is the spring constant k?

Explanation / Answer

From Law of conservation of momentum,

we write

10*v-3*2 = 0

V= 0.6 m/s

b)

mgh = 1/2 kx^2

3*9.8*1 = 0.5*k*10^2

k = 0.588 N/m

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