Here are the initial conditions for the above circuit: Switch #1 is OPEN, Switch
ID: 1510437 • Letter: H
Question
Here are the initial conditions for the above circuit: Switch #1 is OPEN, Switch #2 is OPEN, the capacitor is discharged, so Qcapacitor = 0.
(a) (+2) At time t=0, Switch #2 remains OPEN but Switch 1 is suddenly CLOSED. List the instantaneous values at t=0 of:
VR1 = _________ Volts.
VR2 = _________Volts.
VL = _________Volts.
IL = _________Amps
IC = _________Amps
VC = _________Volts.
(b) (+2) Switch #2 remains OPEN and Switch 1 has now been CLOSED for a long, long time. List the steady-state values of:
VR1 = _________ Volts.
VR2 = _________Volts.
VL = _________Volts.
IL = _________Amps
IC = _________Amps
VC = _________Volts
(c) (+2) Suppose that both Switch #1 and Switch #2 have been closed for a long, long time Switch #1 is now suddenly OPENED. Immediately after Switch #1 is opened, list the instantaneous values of:
VR1 = _________ Volts.
VR2 = _________Volts.
VL = _________Volts.
IL = _________Amps
IC = _________Amps
VC = _________Volts
S2 SA R1 R2 0Explanation / Answer
Inductor doesn't allow the sudden change in current flowing through it, Capacitor wont allow the sudden changes in voltage (potential diff) stored in it.
a) VR1=0, VR2=0, VL= V0, IL=0, IC=0, and VC=0
b) VR1=V0, VR2=0, VL=0, IL =V0/R1 , and VC=0;
c) VR1=0, VR2=(V0/R1)*R2 ,VL= (V0/R1)*R2 , IL = V0/R1 and VC =0;
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