Lab partners Mary and Paul are asked to determine the frequency of a mechanical

Question

Lab partners Mary and Paul are asked to determine the frequency of a mechanical oscillator. They set up an apparatus like the one shown in the diagram below. When they adjust the hanging mass to 46.6 g, they are able to produce 9 antinodes in the string of length L = 1.25 m with nodes at the two ends. They then weigh the 1.25 m long string and find its mass to be 0.524 g. From these measurements, they determine the frequency of the oscillator. What value did they get for the frequency?

Explanation / Answer

the fundamental frequency is

f = n/ 2L sqrt T/ m/l

= 9/ 2 (1.25 m) sqrt ( 46.6 * 10^-3 kg) ( 9.8)/( 0.524 *10^-3 kg/1.25 m)

=118.82 Hz

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.