An external uniform magnetic field of 1.5 T (pointing inward, away from you) is

Question

An external uniform magnetic field of 1.5 T (pointing inward, away from you) is applied to a current carrying conductor. A maximum potential difference of 1E-6V is measured across the top and bottom of the conductor in the picture, current flows to the right, meaning that electrons are moving toward the left. A.What direction is the magnetic force on the electron? B.Because the force, a net charge builds on the conductor, resulting in a potential difference and the therefore an electric field inside the conductor. What is the magnitude of this electric field? C.Maximum voltage occurs when the electric force on the electrons is equal and opposite to the magnetic force. Use this fact to find the drift velocity of the electrons

Explanation / Answer

A)

magnetic force Fb = q(vxB)

v is along -x axis (-i)

B is along -z axis (-k)

charge is negative

Fb is along -(vxB) = j (along y axis) i.e upwards

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(B)

E = dV/d

E = 10^-6/0.1 = 10^-5 V/m

(c)

In equilibrium

Fb = Fe

q*V*B = E*q

v = E/B

v = 10^-5/1.5

v = 6.67*10^-6 m/s

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