In a physics lab students are conducting an experiment to learn about the heat c

Question

In a physics lab students are conducting an experiment to learn about the heat capacity of different materials. The first group is instructed to add 1.5-g copper pellets at a temperature of 92°C to 295 g of water at 16°C. A second group is given the same number of 1.5-g pellets as the first group, but these are now aluminum pellets. Assume that no heat is lost to or gained from the surroundings for either group.

(a) If the final equilibrium temperature of the copper pellets and water is 23°C, how many whole pellets did the first group use in the experiment? The specific heat of copper is 0.0924 kcal/(kg · °C). pellets

(c) What is the equilibrium temperature of the aluminum and water mixture for the second group? °C

Explanation / Answer

a) aS there is no heat loss.

heat absorbed = heat loss

specific heat of water = 1 kcal / kg deg C

suppose there are n pellets then mass of copper = 0.0015n

Q = m C deltaT

0.295 x 1 x (23 - 16 ) = 0.0015n x 0.0924 x (92 - 23)

n = 216

c) specific heat of aluminium = 0.22 kcal / kg deg C

suppose final temp is T.

0.295 x 1 x (T - 16 ) = (0.0015 x 216) x 0.22 x (92 - T)

0.295 T   - 4.72 = 6.56 - 0.07128T

T = 30.8 deg C

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.