Hello, thanks for helping me solve this You take a trip to Pluto and back (round

ID: 1510984 • Letter: H

Question

Hello, thanks for helping me solve this

You take a trip to Pluto and back (round trip 11.5 billion km ), traveling at a constant speed (except for the turnaround at Pluto) of 43500 km/h .

A.) How long does the trip take, in hours, from the point of view of a friend on earth?

Express your answer, with the appropriate units, to three significant figures.

B.) About how many years is this?

Express your answer, with the appropriate units, to three significant figures.

C.) When you return, what will be the difference between the time on your atomic wristwatch and the time on your friend’s?

Express your answer, with the appropriate units, to two significant figures.

Assuming the turn around at Pluto is negligible:

11.5 billion km / 43500 km/h = 264368 hours or 264*10^3 hrs.

This is 30.16 years or 30.2 years.

That's how long your earth based observer should think it took.

Now the difference in time between earth based and moving clocks.

t' = t/sqrt(1-v^2/c^2)

t' = 264368 hours / sqrt(1-(43500 km/h / 1.07925285 × 10^9 kilometres / hour)^2)

t' = 264368.00021473903 hours

Difference then is .00021473903 hours or 0.7730605 seconds or 0.8 s

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