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D Solution Manual Wiley.pcx e WileyPLUS -> C D edugen.wileyplus.com/edugen/student/mainfr.un. :: Apps HP Connected Watch NHL Live Stre- Watch NBA Live Strea × Physics question Chegg. x ABP Practice Assignment GradebookORION ssignment FULL SCREEN PRINTER VERSION BACK ES Chapter 09, Problem 016 016 41 Ricardo, of mass 72 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 40 kg canoe. When the canoe is at rest in the placid water, they exchange seats, which are 3.4 m apart and symmetrically located with respect to the canoe's center. Ricardo notices that the canoe moves 35 cm horizontally relative to a pier post during the exchange and calculates Carmelita's mass. What is it? 28 067 46 13 41 63 71 Number Units the tolerance is +/-2% SHOW HINT GO TUTORIAL LINK TO TEXT LINK TO SAMPLE PROBLEM dy Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER Copyright © 2000-2016 by John Wiley & Sons, Inc. or related companies. All rights reserved I'm Cortana. Ask me anything 11:36 PM 4/27/2016

Explanation / Answer

There are no external forces acting on the Ricardo-Carmelita-canoe system. Therefore, the center of mass of this system does not change its position.

The initial positions of Ricardo (xR), Carmelita (xC), and the canoe (xb) relative to the log are,
xR = 0
xC = 3.4 m
xb = 1.7 m

So, the initial position of the center of mass of the RCc system is
Xc.o.m initial = (mR*xR + mC * xC + mb*xb)/(mR + mC + mb)

Now they exchange their seats,
xR' = 3.05
xC' = -0.35
xb' = 1.35

Xc.o.m final = (mR*xR' + mC * xC' + mb*xb')/(mR + mC + mb)

Equating the two,
(mR*xR + mC * xC + mb*xb)/(mR + mC + mb) = (mR*xR' + mC * xC' + mb*xb')/(mR + mC + mb)
(mR*xR + mC * xC + mb*xb) = (mR*xR' + mC * xC' + mb*xb')
(72 * 0 + mC * 3.4 + 40 * 1.7) = (72 * 3.05 - mC * 0.35 + 40 * 1.35)
mC = 54.8 Kg

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