In the figure (Figure 1) a conducting rod of length L = 34.0 cm moves in a magne

Question

In the figure (Figure 1) a conducting rod of length L = 34.0 cm moves in a magnetic field B? of magnitude 0.460 T directed into the plane of the figure. The rod moves with speed v = 5.40 m/s in the direction shown.

i. What is the potential difference between the ends of the rod?

ii. Which point, a or b, is at higher potential?

iii. When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod?

iv. What is the direction of the electric field within the rod?

v. When the charges in the rod are in equilibrium, which point,a or b, has an excess of positive charge?

vi. What is the potential difference across the rod if it moves parallel to ab?

vii. What is the potential difference across the rod if it moves directly out of the page?

Explanation / Answer

i) Potential diff = rate of change of flux = BLv =0.46*0.34*5.4 = 0.84456 V

ii) point b is at higher potential

iii) E = - dV/dx = 0.84456/0.34 = 2.484 V/m

iv) From b to a

v) b has an excess of positive charge

vi)potential difference will be zero because there will not be change in flux

vii)potential difference will be zero because there will not be change in flux

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