. Let the magnetic field have a magnitude of 2 . 3 T , and the velocities of the
ID: 1511150 • Letter: #
Question
. Let the magnetic field have a magnitude of 2.3 T, and the velocities of the particles be fired in at a speed of 6 × 106m/s.
a) How far above/below the entrance will the positive charges emerge if the beam consists of protons?
b) How far above/below the entrance will the positive charges emerge if the beam consists of particles (2 protons and 2 neutrons bound together in a nucleus)?
c) How far above/below the entrance will the negative charges emerge if the beam consists of electrons?
Please show all steps!
Explanation / Answer
a)centripetal force = magnetic force
mv^2/r = qvB
r = mv/qB
It will emerge at a distance of diameter = 2r = 2* 1.67 *10^-27 * 6*10^6/[1.6*10^-19*2.3] = 0.0545 m
b) In this case mass becomes 4 times and charge becomes 2 twice, so diameter will be double.
It will emerge at a distance of diameter = 2r = 2*4* 1.67 *10^-27 * 6*10^6/[2*1.6*10^-19*2.3] = 0.109 m
c) Here charge is 1.6*10^-19 C but mass is 9.1*10^-31kg
It will emerge at a distance of diameter = 2r = 2* 9.1 *10^-31 * 6*10^6/[1.6*10^-19*2.3] = 0.0000297 m
= 0.0297 mm
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