Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

the magnetic field points away from the wire on both the left and right the magn

ID: 1511155 • Letter: T

Question

the magnetic field points away from the wire on both the left and right the magnetic field points towards the wire on both the left and right side the magnetic field point into the paper on the left and out of the paper on the right the magnetic field point out of the paper on the left and into the paper on the right What force is exerted on a 1.4 muC particle in a uniform electric field of 32.000 N/C? You have a uniform electric field described by the vector Erightarrow = (2i - 8j + 4k)N/C and a flat surface describe by the vector Arightarrow=(3i+2J+5k)m^2. What is the electric flux through this surface? A 5 muF capacitor is connected to a 9 V battery. What is the charge stored on the capacitor?

Explanation / Answer

11) The force is charge times the electric field.

Hence F = qE = 1.4*10^-6*32000 = 0.0448 N

12) E = 2 i^ -8 j^ + 4 k^ N/C

A = 3 i^ + 2j^ + 5k^ m^2

The electric flux is integral E. dA over the surface but here the electric field is zero, the electric flux will be E.A

So, electric flux = 2*3 - 8*2+4*5 = 10 N m^2/C

13) The charge stored on capacitor will be:

Q = CV = 5*10^-6*9 = 45 mu C.