The cross-sectional area of an adjustable single loop is reduced from 1 m^2 to 0

Question

The cross-sectional area of an adjustable single loop is reduced from 1 m^2 to 0.25 m^2 in 0.1 s. What is the average emf that is includuced in this coil if it is in a region where B = 2 T upward, and the coil's plane is perpendicular to B? A rectangular wire loop (area 0.20 m^2) of one turn is placed in a region where the magnetic field is perpendicular lo the plane of the loop. The magnitude of the magnetic field varies according to It (4 + 2t^2) T, where t is in seconds. What is the magnetic flux cutting the loop when t = 2 see? A rod slides across a magnetic field. If the length of the rod is 15 cm, its speed is 30 cm/s a a magnetic Held 0.25 T is directed at right angle to the rod, find the induced cmf in the

Explanation / Answer

13) induced emf = rate of change of flux

= B.dA/dt = 2*(1-0.25)/0.1 = 15 V

14) Flux =BA = (4+2t^2)*0.2 = 2.4 T-m^2

15)Emf = AdB/dt = 0.2*4t = 0.2*4*2 =1.6 V

16) Emf = BvL = 0.25*0.30*0.15 = 0.0113 V = 11.3mV

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