An experimental bicycle wheel is placed on a test stand so that it is free to tu

Question

An experimental bicycle wheel is placed on a test stand so that it is free to turn on its axle. If a constant net torque of 4.00 N · m is applied to the tire for 4.00 s, the angular speed of the tire increases from 0 to 100 rev/min. The external torque is then removed, and the wheel is brought to rest by friction in its bearings in 140 s.

(a) Compute the moment of inertia of the wheel about the rotation axis. kg·m (b) Compute the friction torque. N·m the total number of revolutions made by the wheel in the 140-s time interval. rev

Explanation / Answer

1)Torque=moment of inertia * angular accelaration
=> 4=I*(100-0)/4
=>I=0.16 kg.m²

Ans- Torque is 0.16 kgm^2

2)friction torque= I * angular acc.
= 0.16*(100-0)/140
=0.114Nm

Ans- Friction torque is 0.114 Nm

3)no of revolutions= (1/2)(100/140)(140)²
=6250rev

Ans- total no of revolution are 6250

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