A hydraulic press has one piston with a diameter of 1 inch and the other piston

Question

A hydraulic press has one piston with a diameter of 1 inch and the other piston has a 9 inch diameter. If a 4-lb force is applied to the smaller piston, the force exerted on the larger piston will be: 2.3 lb 51b 12 lb 361b 81 lb Two identical blocks of ice float in water as shown. Then: the 2 blocks displace equal volumes of water since they have the same weight block A displaces a greater volume of water since the pressure acts on a smaller bottom block A displaces a greater volume of water since its submerged end is lower in the water block B displaces a greater volume of water since the pressure is less on its bottom block B displaces a greater volume of water since its submerged end has a greater area

Explanation / Answer

4)

given d1 = 1 inch

d2 = 9 inch

Apply Pascal's law

P1 = P2

F1/A1 = F2/A2

F1/(pi*d1^2/4) = F2/(pi*d2^2/4)

F1/d1^2 = F2/d2^2

F2 = F1*(d2/d1)^2

= 4*(9/1)^2

= 4*81

= 324 N

I am sure the answer is not in the given options.

5)

A) The 2 blocks displace equal volume of water since they hace the same weight

in the equilibirum,

Net force acting on the block = 0

B - m*g = 0 (here B is buoynat force exerted by water)

B = m*g

rho_water*V*g = m*g (here V is volume of the block sumerged in water)

V = m/rho_water

from the above equation in both cases, m is same.

so, V is also same.

so, The 2 blocks displace equal volume of water since they hace the same weight

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